[ACCEPTED]-ruby regex: match and get position(s) of-regex

Accepted answer

Score: 61

Using Ruby 1.8.6+, you can do this:

require 'enumerator' #Only for 1.8.6, newer versions should not need this.

s = "AustinTexasDallasTexas"
positions = s.enum_for(:scan, /Texas/).map { Regexp.last_match.begin(0) }

This 1 will create an array with:

=> [6, 17]

Score: 31

Sort of, see String#index

"AustinTexasDallasTexas".index /Texas/
=> 6

Now, you could extend the String 1 API.

class String
  def indices e
    start, result = -1, []
    result << start while start = (self.index e, start + 1)
    result
  end
end
p "AustinTexasDallasTexas".indices /Texas/
=> [6, 17]

Score: 3

"AustinTexasDallasTexas".gsub(/Texas/).map { Regexp.last_match.begin(0) }
  #=> [6, 17]

0

Source: stackoverflow.com

More Related questions

Matching balanced parenthesis in Ruby using recursive regular expressions like perl

How do I strip parenthesis from a string in Ruby?

Match a string against multiple patterns

Regular expression for only allow numbers and must end with '#' sign

How do I get the match data for all occurrences of a Ruby regular expression in a string?

Remove "@" sign and everything after it in Ruby

ruby on rails, replace last character if it is a * sign

Escape special chars in RegEx?

Regex to find unmatched parentheses

Ruby regex: replace non-word chars that are not space chars

Cookie Warning

We use cookies to improve the performance of the site. By staying on our site, you agree to the terms of use of cookies.