[ACCEPTED]-$1 and \1 in Ruby-regex

Accepted answer

Score: 82

\1 is a backreference which will only work 3 in the same sub or gsub method call, e.g.:

"foobar".sub(/foo(.*)/, '\1\1') # => "barbar"

$1 is 2 a global variable which can be used in later 1 code:

if "foobar" =~ /foo(.*)/ then 
  puts "The matching word was #{$1}"
end

Output:

"The matching word was bar"
# => nil

Score: 30

Keep in mind there's a third option, the 10 block form of sub. Sometimes you need it. Say 9 you want to replace some text with the reverse 8 of that text. You can't use $1 because 7 it's not bound quickly enough:

"foobar".sub(/(.*)/, $1.reverse)  # WRONG: either uses a PREVIOUS value of $1, 
                                  # or gives an error if $1 is unbound

You also can't 6 use \1, because the sub method just does a simple 5 text-substitution of \1 with the appropriate 4 captured text, there's no magic taking place 3 here:

"foobar".sub(/(.*)/, '\1'.reverse) # WRONG: returns '1\'

So if you want to do anything fancy, you 2 should use the block form of sub ($1, $2, $`, $' etc. will 1 be available):

"foobar".sub(/.*/){|m| m.reverse} # => returns 'raboof'
"foobar".sub(/(...)(...)/){$1.reverse + $2.reverse} # => returns 'oofrab'

Source: stackoverflow.com

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