[ACCEPTED]-Can parallel traversals be done in MATLAB just as in Python?-for-loop

Accepted answer

Score: 20

If x and y are column vectors, you can do:

for i=[x';y']
# do stuff with i(1) and i(2)
end

(with 2 row vectors, just use x and y).

Here is an 1 example run:

>> x=[1 ; 2; 3;]

x =

     1
     2
     3

>> y=[10 ; 20; 30;]

y =

    10
    20
    30

>> for i=[x';y']
disp(['size of i = ' num2str(size(i)) ', i(1) = ' num2str(i(1)) ', i(2) = ' num2str(i(2))])
end
size of i = 2  1, i(1) = 1, i(2) = 10
size of i = 2  1, i(1) = 2, i(2) = 20
size of i = 2  1, i(1) = 3, i(2) = 30
>>

Score: 8

Tested only in octave... (no matlab license). Variations 1 of arrayfun() exist, check the documentation.

dostuff = @(my_ten, my_one) my_ten + my_one;

tens = [ 10 20 30 ];
ones = [ 1 2 3];

x = arrayfun(dostuff, tens, ones);

x

Yields...

x =

   11   22   33

Score: 6

If I'm not mistaken the zip function you 10 use in python creates a pair of the items found in list1 and list2. Basically it still is a 9 for loop with the addition that it will 8 retrieve the data from the two seperate 7 lists for you, instead that you have to 6 do it yourself.

So maybe your best option 5 is to use a standard for loop like this:

for i=1:length(a)
  c(i) = a(i) + b(i);
end

or whatever 4 you have to do with the data.

If you really 3 are talking about parallel computing then 2 you should take a look at the Parallel Computing Toolbox for matlab, and 1 more specifically at parfor

Score: 2

I would recommend to join the two arrays 5 for the computation:

% assuming you have column vectors a and b
x = [a b];

for i = 1:length(a)
    % do stuff with one row...
    x(i,:);
end

This will work great 4 if your functions can work with vectors. Then 3 again, many functions can even work with 2 matrices, so you wouldn't even need the 1 loop.

Score: 0

for (x,y) in zip(List1, List2):

should be for example:

>> for row = {'string' 10
>>           'property' 100 }'
>>    fprintf([row{1,:} '%d\n'], row{2, :});
>> end
string10
property100

This is tricky because 3 the cell is more than 2x2, and the cell 2 is even transposed. Please try this.

And 1 this is another example:

>> cStr = cell(1,10);cStr(:)={'string'};
>> cNum=cell(1,10);for cnt=1:10, cNum(cnt)={cnt};
>> for row = {cStr{:}; cNum{:}}
>>    fprintf([row{1,:} '%d\n'], row{2,:});
>> end
string1
string2
string3
string4
string5
string6
string7
string8
string9
string10

Score: 0

If I have two arrays al and bl with same 3 dimension No 2 size and I want to iterate 2 through this dimension (say multiply al(i)*bl(:,i)). Then 1 the following code will do:

al = 1:9;
bl = [11:19; 21:29];

for data = [num2cell(al); num2cell(bl,1)]

    [a, b] = data{:};
    disp(a*b)

end

Source: stackoverflow.com

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