[ACCEPTED]-PHP - Summing an array of decimal values-sum

Accepted answer

Score: 12

Given that this seems impossible to reproduce, to 6 me it sounds like a problem with your PHP 5 environment itself.

Check php.ini for a setting 4 called "precision", and make sure it's set 3 to the default of 14 significant figures. I 2 can't imagine why this would be changed, but 1 it would definitely have an impact.

Score: 4

You can try using array_sum() instead and use (float) to 5 cast the values. Additionally I would make 4 sure that the values in the array are in 3 the correct format (1.45 and not 1,45). HTH.

Update

Btw. you 2 can use "is_float()" to check 1 every parameter in the array.

Score: 3

Can't reproduce this.

php > $oldArray = array(0, .1, .2, .3, .4, .5, .6, .7, .8, .9);                                                    
php > $myVar = 0.0;
php > for($k=0;$k < count($oldArray);$k++)
php > {
php { $myVar += $oldArray[$k];
php { }
php > print_r($myVar);
4.5

EDIT: I tried the code 2 in your comment, and it's fine. Like AlbertoPL, I 1 suspect the problem is elsewhere.

php > $oldArray = array(0.01,1000.11,988.92,978.22,964.01,953.07,948.82,917.26,902.56,913.21,904.08,898.86,892.79);
php > $myVar = 0.0000;
php > for($k=1;$k<10;$k++)
php >   $myVar += $oldArray[$k];
php > print_r($myVar);
8566.18

Score: 0

Make your own implementation:

function sum_array($arr){
 $count = 0;
  foreach ($arr as $val){
    if (!is_numeric($val) // neglect any non numeric values
      {
        $error = true;
        continue;
      }
      else{
        $count = $count + ($val*1); //casting to numeric if the value supplied as string
      }
  }
  return $count
}

echo sum_array($myArray);

Source: stackoverflow.com

[ACCEPTED]-PHP - Summing an array of decimal values-sum

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