[ACCEPTED]-Try Catch cannot work with require_once in PHP?-php

Accepted answer
Score: 60

You can do it with include_once or file_exists:

try {
    if (! @include_once( '/includes/functions.php' )) // @ - to suppress warnings, 
    // you can also use error_reporting function for the same purpose which may be a better option
        throw new Exception ('functions.php does not exist');
    // or 
    if (!file_exists('/includes/functions.php' ))
        throw new Exception ('functions.php does not exist');
        require_once('/includes/functions.php' ); 
catch(Exception $e) {    
    echo "Message : " . $e->getMessage();
    echo "Code : " . $e->getCode();


Score: 10

As you can read here : (emph mine)

require() is 11 identical to include() except upon failure 10 it will also produce a fatal E_COMPILE_ERROR level error. In other words, it 9 will halt the script

This is about require, but 8 that is equivalent to require_once(). This 7 is not a catchable error.

By the way, you 6 need to enter the absolute path, and I don't 5 think this is right:

 require_once( '/includes/functions.php' ); 

You might want something 4 like this

require_once( './includes/functions.php' ); 

Or, if you're calling this from 3 a subdir or from a file that is included 2 in different dirs, you might need something 1 like

require_once( '/var/www/yourPath/includes/functions.php' ); 
Score: 6

This should work, but it is a bit of a hack.

if(!@include_once("path/to/script.php")) {
    //Logic here


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