[ACCEPTED]-Passing a parameter as a pointer in JavaScript-pointers

Accepted answer

Score: 12

You can achieve the effect you want by taking 2 advantage of the fact that Javascript passes 1 objects by reference:

var o = { };

(function (p) {
    p.fn = function () {
        alert('test');
    };
})(o);

o.fn();

Score: 3

You're better off using the language as 4 intended rather than trying to bend it to 3 fit idioms that only make sense in a language 2 constructed according to a different set 1 of principles.

var o = (function(p) {
    return function() {
        alert('test');
    };
})();

o();

Score: 1

When you pass in variable o in your example, you're 10 passing an undefined value, not a reference 9 to anything. What you'd need to do, is send 8 the objects parent. In this case, the window 7 object (assuming you're using a browser).

(function (p, name) {
    p[name] = function() {
       alert('test');
    };
})(window, "o");
o();

This 6 passes in the window object, and the name 5 of your new function. Then it assigns your 4 function to the window, and it now available 3 to be called. Unless you're going to use 2 closures, though, I'd suggest just assigning 1 the function directly.

function o() {
    alert('test');
};
o();

Source: stackoverflow.com

[ACCEPTED]-Passing a parameter as a pointer in JavaScript-pointers

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