[ACCEPTED]-Passing a gcc flag through makefile-llvm

Accepted answer
Score: 12

Looks like you could add the -fPIC (for 11 position-independent code, something you 10 want for a shared library that could be 9 loaded at any address) by setting shell 8 variables:


Looking at Makefile.rules, these will be picked 7 up and used. Seems strange that it wasn't 6 there to begin with.


Actually, reading 5 more in the makefiles, I found this link 4 to the LLVM Makefile Guide. From Makefile.rules, setting either 3 SHARED_LIBRARY=1 or LOADABLE_MODULE=1 (which 2 implies SHARED_LIBRARY) in Makefile will 1 put -fPIC in the compiler flags.

Score: 5

If you are moderately convinced that you 13 should use '-fPIC' everywhere (or '-m32' or '-m64', which 12 I need more frequently), then you can use 11 the 'trick':

CC="gcc -fPIC" ./configure ...

This assumes a Bourne/Korn/POSIX/Bash 10 shell and sets the environment variable 9 CC to 'gcc -fPIC' before running the configure script. This 8 (usually) ensures that all compilations 7 are done with the specified flags. For 6 setting the correct 'bittiness' of the compilation, this 5 sometimes works better than the various 4 other mechanisms you find - it is hard for 3 a compilation to wriggle around it except 2 by completely ignoring the fact you specified 1 the C compiler to use.

Score: 1

Another option is to pass -fPIC directly 1 to make in the following way:


More Related questions