[ACCEPTED]-How to initialize argv array in C-c
char* dummy_args[] = { "dummyname", "arg1", "arg2 with spaces", "arg3", NULL };
int main( int argc, char** argv)
{
argv = dummy_args;
argc = sizeof(dummy_args)/sizeof(dummy_args[0]) - 1;
// etc...
return 0;
}
One thing to be aware of is that the standard 6 argv
strings are permitted to be modified. These 5 replacement ones cannot be (they're literals). If 4 you need that capability (which many option 3 parsers might), you'll need something a 2 bit smarter. Maybe something like:
int new_argv( char*** pargv, char** new_args)
{
int i = 0;
int new_argc = 0;
char** tmp = new_args;
while (*tmp) {
++new_argc;
++tmp;
}
tmp = malloc( sizeof(char*) * (new_argc + 1));
// if (!tmp) error_fail();
for (i = 0; i < new_argc; ++i) {
tmp[i] = strdup(new_args[i]);
}
tmp[i] = NULL;
*pargv = tmp;
return new_argc;
}
That 1 gets called like so:
argc = new_argv( &argv, dummy_args);
or simply put, does this work (sorry its 1 3 years late ;) ) ?
int argc ;
char * argv[3] ;
char p1[16] ;
char p2[16] ;
char p3[16] ;
memcpy ( p1, "mainwindow", 9 ) ;
memcpy ( p2, "–SizeHint5", 10 ) ;
memcpy ( p3, "120x240", 7 ) ;
argc = 3 ;
argv[0] = p1 ;
argv[1] = p2 ;
argv[2] = p3 ;
QApplication app(argc, argv);
Initialisation like that is only available 4 at declaration time, and (presumably) you've 3 declared argv as a parameter to your function 2 (main
I assume).
You will have to assign each 1 individually in this instance.
To conform with newer compilers, I would 2 do this (as long as you don't want to change 1 the strings):
char* argv[] = {const_cast<char*> ("program_name"),
const_cast<char*> ("-arg1"),
const_cast<char*> ("string_to_arg1"),
const_cast<char*> ("-arg2"),
const_cast<char*>("-arg3"),
NULL};
int argc = sizeof (argv) / sizeof (char*) - 1;
QApplication app(argc, argv);
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