[ACCEPTED]-initializing a const multidimensional array in c++-multidimensional-array

Accepted answer

Score: 17

you could make 2d array?

string aArray[][2] = {{"wall", "brick..."}, 
                               {"glasses", "corrective eye tool thingymajig"},
                               {"calculator", "number cruncher"}};

not sure if the 6 syntax is right but i hope you get the concept.

it's 5 an array inside another array.

EDITED: i 4 removed the NUM_WORDS from the first square 3 bracket. you can't declare multi dimentional 2 array from variables.. sorry i forgot about 1 that. i just tested it and it works.

Score: 6

Use a struct array:

typedef struct
{
    string Word;
    string Hint;
}
WORDDEF;

const WORDDEF WordList[] =
{
    {"wall", "brick..."},
    {"glasses", "worn on head"},
    ...
};

Then you refer to them 1 as:

printf ("For entry %d, Word is %s, Hint is %s\n", 1, WordList[1].Word, WordList[1].Hint);

Score: 0

huh... maybe you should use pair struct?

std::pair<std::string, std::string> WORDS[10] = { make_pair("wall", "brick"), 
                                                  make_pair("glasses, worn") }

now, you 2 can use WORDS[i].first -- as the unknown 1 word

and WORDS[i].second as its hint.

Score: 0

Here is a simple example That will give 6 you a 2 dimensional array[2][2] from the 5 other two arrays that you already have that 4 you can use as a starting point.

#include "stdafx.h"
#include "iostream"
#include "string"

#define NUM_WORDS 2
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
    const string WORDS[NUM_WORDS] = {"wall", "glasses"};
    const string HINTS[NUM_WORDS] = {"brick", "worn on head"};

    string hw[NUM_WORDS][NUM_WORDS];

    for(int i=0; i < NUM_WORDS; i++)
        for(int j=0; j < NUM_WORDS; j++)
        {
            if(i > 0)
                hw[i][j] = HINTS[j];
            else if(j > 0)
                hw[i][j] = WORDS[i+1];
            else
                hw[i][j] = WORDS[i];
        }
    for(int i=0; i < NUM_WORDS; i++)
        for(int j=0; j < NUM_WORDS; j++)
        {
            cout << "hw[" << i << "][" << j << "]= " << hw[i][j] << endl;
        }

    char c;
    cin.get(c);
    return 0;
}

For some 3 reason no matter what I do the box will 2 not let me copy and paste the code in so 1 that it formats correctly. sorry.

Source: stackoverflow.com

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