javascript python java c# php android html jquery c++ css ios mysql sql r node.js arrays reactjs c asp.net json ruby-on-rails .net sql-server swift python-3.x objective-c django angular angularjs excel regex pandas ruby iphone ajax linux xml vba asp.net-mvc spring laravel database wordpress typescript string wpf mongodb windows xcode postgresql bash oracle git vb.net amazon-web-services multithreading list firebase flutter eclipse spring-boot dataframe azure react-native algorithm docker macos forms image visual-studio scala powershell function twitter-bootstrap numpy api performance selenium winforms python-2.7 matlab vue.js sqlite apache hibernate entity-framework loops rest shell facebook express android-studio csv linq maven qt swing unit-testing file tensorflow

[ACCEPTED]-How to set the filename when downloading a file?-azure

Accepted answer
Score: 12

You should return a new FileContentResult 2 and your action must return FileResult instead 1 of ActionResult for ex.:

public virtual FileResult DownloadFile(long fileId)
{
     string path = ExcelGenerationCode(fileName);
     return File(path, "application/vnd.ms-excel","donwload.xls");
}
Source: stackoverflow.com

More Related questions

How to replace Microsoft.WindowsAzure.Storage with Microsoft.Azure.Storage.Blob

Azure Blob 400 Bad request on Creation of container

How to trigger button click in MVC 4

How to resize and save an image which uploaded using file upload control in c#

Create DropDownListFor from SelectList with default value

How would you detect the current browser in an Api Controller?

Validation Error: The value 'on' is not valid for <<property name>>

Why is mdf file not appearing in the App_Data folder?

How to get client IP address in MVC 4 controller?

MVC Razor C# Variable used for HTML img tag src